Packers' Woodson NFL Defensive Player of the Year

To no one's real surprise -- especially not any Packer fans -- CB Charles Woodson was today named the NFL Defensive Player of the Year.

According to a report, "Woodson won the voting of 50 national media members that cover the NFL with 28 votes. New York Jets cornerback Darrelle Revis finished second with 14. Denver Broncos end Elvis Dumervil and New Orleans Saints safety Darren Sharper tied for third with three votes. Vikings end Jared Allen received two.

"Woodson finished tied for the league lead with nine interceptions and three returned for a touchdown. He became the fourth player in league history to record at least nine interceptions and two sacks in a season.

"Woodson, the first cornerback to win the award since Deion Sanders in 1994, finished with a career-best 81 total tackles, with 21 passes defensed, four forced fumbles and one recovery, and three quarterback hits."

Woodson joins the late Reggie White as the only Packer defenders to ever receive this award.

You can read more about Woodson's award here and here.

The Packers will be holding a news conference for Woodson at approximately 2 p.m. Central time today. It will be streamed live. You can view it by clicking here and then selecting the event (if need be) where prompted.

Congratulations, Mr. Woodson. A remarkable season. The only thing missing was that ring that you and so many others wanted to see you get.